sin A + cos B =
a)√3/√5
b)√6/√5
c)2√3/√5
d)2√2/√5
Answers
Answered by
0
Answer:
Correct option is
D
5
(
5
+
3
)
sinB
sinA
=
2
3
⇒
sin
2
B
sin
2
A
=
4
3
⇒sin
2
A=3
4
sin
2
B
−(i)
cosB
cosA
=
2
5
cos
2
B
cos
2
A
=
4
5
⇒cos
2
A=5
4
cos
2
B
−(ii)
(i)+(ii)=1
∴3
4
sin
2
B
+5
4
cos
2
B
=1
∴3sin
2
B+5(1−sin
2
B)=4
∴1=2sin
2
B
⇒sinB=
2
1
B=45
sinA=
2
6
cosB=cos45=
2
1
cosB
cosA
=
2
5
cosA=
2
2
5
⇒tanA+tanB
=
cosA
sinA
+
cosB
sinB
=
2
2
5
2
6
+
2
1
2
1
=
5
3
+1
=
5
3
+
5
Attachments:
Similar questions