Question

sin. A cos B + cos. A sin B + cos. A cos' B + sin A sin B = 1​

Answer 1

Answer:

#sin A sin B - cos A cos B + 1 = 0

#=>cos A cos B-sin A sin B = 1

⇒ cos(A + B) = 1 = cos 0)

⇒ A=2n-B, where ne Z

Now

1+ cot A tan B

→ 1 + cot (2nm - B)tan B

⇒1-cot (B)tan B=1-1=0

Answer 2

refer the attachment hope its help u