Math, asked by aabidahmad1976, 4 months ago


(sin A + cosA)2 + (sinA-cosA)2​

Answers

Answered by Anonymous
4

Answer:

= 2sinA + 2cosA + 2sinA - 2cosA

= 4 sinA

Answered by mdmdarshad67
1

Step-by-step explanation:

(sinA + cosA)^2 + ( sinA - cosA)^2

= sin^2A +cos^2A + 2sinA cosA + sin^2A + cos^2A - 2sinA cosA

= 1 +1 ( sin^2A+ cos^2A= 1)

= 2

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