Sin a + cosec a=10/3.find sin^2a+ cosec^2a
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Answer:
Heyyyaaa!!❤
The answer is 82/9.
Step-by-step explanation:
=SinA+cosecA=10/3
squaring both the sides,
we get,
=(sinA+cosecA)^2=(10/3)^2
=sin^2A+2sinAcosecA+cosec^2A=100/9
(sin and cosec are inverse ratios
which when multipled give 1)
=Sin^2A+2sinA*1/sinA+cosec^2A=100/9
=sin^2A+2(1)+cosec^2A=100/9
=sin^2A+cosec^2A=100/9-2
=sin^2A+cosec^2A=100-18/9
=sin^2A+cosec^2A=82/9
For better explanation check the attachment!
Thank you ❤
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