Question

Sin a + cosec a=10/3.find sin^2a+ cosec^2a

Answer 1

Answer:

Heyyyaaa!!❤

The answer is 82/9.

Step-by-step explanation:

=SinA+cosecA=10/3

squaring both the sides,

we get,

=(sinA+cosecA)^2=(10/3)^2

=sin^2A+2sinAcosecA+cosec^2A=100/9

(sin and cosec are inverse ratios

which when multipled give 1)

=Sin^2A+2sinA*1/sinA+cosec^2A=100/9

=sin^2A+2(1)+cosec^2A=100/9

=sin^2A+cosec^2A=100/9-2

=sin^2A+cosec^2A=100-18/9

=sin^2A+cosec^2A=82/9

For better explanation check the attachment!

Thank you ❤