Math, asked by ADAMSHARIEFF, 1 year ago

(sin A + cosec A)^2+(cos A+sec A)^2=7+tan^2A+cot^2A

Answers

Answered by sanjay323
10
(sin^2A+cosec^2A+2.sinA.cosecA)+(cos^2A+... 
=(sin^2A+cos^2A)+(2.sinA.cosecA)+(2.co... 
=1+2+2+(cosec^2A+sec^2A) 
=5+((sin^2A+cos^2A)/(cos^2A.sin^2A)) 
=5+(sec^2A.cosec^2A) 
=5+(1+tan^2A)(1+cot^2A) 
=5+1+cot^2A+tan^2A+tan^2A.cot^2A 
=5+1+1+cot^2A+tan^2A 
=7+tan^2A+cot^2A 

HOPE IT HELPS

MARK BRAINLIEST

sanjay323: ok
ADAMSHARIEFF: +(2.co complete this plz i cant understand it
sanjay323: oh
sanjay323: =sin^2A +2sinAcscA +csc^2A +cos^2A +2cosAsecA +sec^2A 
=sin^2A +cos^2A +2(1) +2(1) +csc^2A +sec^2A 
=5 +(1 +cot^2A) + (tan^2A+1) 
=7 +tan^2A +cot^2A
sanjay323: this is the second answer
ADAMSHARIEFF: thank u very much
sanjay323: where there are = there the next line starts ok
sanjay323: wlcm
ADAMSHARIEFF: kkk
sanjay323: hmm
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