Question

Sin a + cosec a whole square + cos a + sec a whole square equal to 7 + tan square theta+cotsquare thetha

Answer 1

Answer:

(sinA+cosecA)^2 + (cosA+secA)^2

= (sinA)^2 +(cosecA)^2 +2 +(cosA)^2 +(secA)^2 + 2

= 5+(1+(cotA)^2) + (1 +(tanA)^2)

=7 + (tanA^2 +(cotA)^2

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Step-by-step explanation: