Sin A= cosec B prove that A+B=90°
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Answered by
0
Answer:
By identity, Sec A = Cosec (90-A)
Sec A = Sec (90-B)
Sec will be eliminated
= A=90 - B
= A+B= 90
Answered by
1
Answer:
=sinA=cosecB
cosec(90-A)=cosecB
90-A=B
A+B=90
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