Math, asked by tarun1864, 10 months ago

Sin A= cosec B prove that A+B=90°

Answers

Answered by gauthamleju10
0

Answer:

By identity, Sec A = Cosec (90-A)

Sec A = Sec (90-B)

Sec will be eliminated

= A=90 - B

= A+B= 90

Answered by bhargav129
1

Answer:

=sinA=cosecB

cosec(90-A)=cosecB

90-A=B

A+B=90

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