Question

( sin A + cosecA)sqauare + ( cos A + sec A ) square =7+tansquare A + cot square A​

Answer 1

Answer:

Step-by-step explanation:

(sin + cosec )^2 = sin^2 + cosec^2 + 2

                          = sin^2 + 1 + cot^2 + 2

                          = sin^2 + 3 + cot^2

(cos + sec)^2 = cos^2 + sec^2 + 2

                     = cos^2 + 1 + tan^2 +2

                     = cos^2 + 3 + tan^2

Adding the two

sin^2 + 3 + cot^2 + cos^2 + 3 + tan^2 = 7 + tan^2 + cot^2