Question

Sin A ( Cot A +3)(3cot A +1 )- 3 Cosec A - 10 Cos A=?​

Answer 1

Step-by-step explanation:

SinA(3Cot²A+10CotA+3)- 3CosecA-10cosA

=

$3 { {cot}^{2}A} \: {sinA} + {10cotA} \: {sinA} + 3sinA - 3cosecA - 10cosA$

=3Cos²A/sinA+10cosA+3sinA-3/sinA-10cosA

=3(cos²A-1)/sinA+3sinA

=3(-Sin²A)/sinA+3sinA

=(-3)SinA+3sin A