Question

sin(A+D) + sin (B+C) =0 if ABCD is a cyclic quadrilateral ​

Answer 1

Step-by-step explanation:

In a cyclic quadrilateral, sum of opposite angles is 180.

So, A+C=180⇒C=180−A⇒sinC=sin(180−A)=sinA

B+D=180⇒D=180−B⇒sinD=sin(180−B)=sinB

So,

sinA+sinB−sinC−sinD

=sinA+sinB−sinA−sinB

=0

Hence, A is correct.

Answer 2

Answer:

PLEASE FOLLOW ME..................