Question

(sin A + sec A)² + ( cos A + cosec A ) ²= (1+ sec A cosec A )²

Answer 1

taking L.H.S

consider (^) = power square


(sinA + secA)^ + (cosA + cosecA)^

(1/cosecA + secA)^ + ( 1/ secA. + cosecA)^

[( 1 + secA× cosecA)/cosecA]^ + [ (1 +cosecA×secA)/secA]^

(1 + secA×cosecA)^/cosecA^ + ( 1 + cosecA×secA)^/ secA^

taking common ,

(1 + secA× cosecA)^ (1/cosec^A + 1/ sec^A)

(1 + secA× cosecA)^ (sin^A +cos^A)

(1 + secA×cosecA)^ (1)

( 1 + secAcosecA)^

it has proved, L.H.S = R.H.S

Answer 2

Answer:

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Step-by-step explanation:

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