Question

(sin A/sec A+ tan A-1) +(COS A/cosec A + cot A -1) =1​

Answer 1

Step-by-step explanation:

(sinA/secA+tanA-1)+(cosA/cosecA+cotA-1)

=(sinAcosA/1+sinA-cosA)+(sinAcosA/1+cosA-sinA)

=(sinAcosA/1+sinA-cosA)+{sinAcosA/1-(sinA-cosA)}

=sinAcosA{1-(sinA-cosA)}+sinAcosA(1+sinA-cosA)/{1²-(sinA-cosA)²

=sinAcosA[1-sinA+cosA+1+sinA-cosA/1-(sin²A+cos²A-2sinAcosA]

=sinAcosA[2/1-(1-2sinAcosA)]

=sinAcosA[2/2sinAcosA]

=sinAcosA/sinAcosA