Question

sin A−sin (2400−A)+sin (2400+A)=​

Answer 1

Answer:

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Answer 2

Answer:

n=1/4

Step-by-step explanation:

f(x)=sinxsin(240

o

−x)sin(240

o

+x)

=sinx[

2

cos2x−cos(480

o

)

][sinAsinB=

2

cos(A−B)−cos(A+B)

]

=

2

sinx[cos2x+

2

1

]

=

2

sinx[1−2sin

2

x+

2

1

]

=

4

sin3x

[sin3x=3sinx−4sin

3

x]

range of f(x)ϵ[−

4

1

,

4

1

]=[−n,n]

n=

4

1