Question

sin A sin 2A + sin 3A sin 6A

Answer 1

Step-by-step explanation:

sinA sin2A + sin3A sin 6A

Let perpendicular be = p

& hypotenuse be = h

Now, equation is

(sin = perpendicular/hypotenuse)

sinA sin2A + sin3A sin6A

pA/h × p2A/h + p3A/h × p6A/h

(2p^2A^2)/h^2 + (18p^2A^2)/h^2

(20p^2A^2)/h^2

Here is your solution.

I hope it will help you.