Math, asked by bsrihas101, 1 year ago

sin
A+ Sin 3A+ Sin 5A+ Sin 7A.​

Answers

Answered by himanshu9096
1

Answer:

=sinA+sin3A+sin5A+sin7A.

=sin16A.

Answered by coolammy02
3
SinA+sin7A = 2sin[(7A+A)/2]cos[(7A-A)/2]
= 2sin4Acos3A
Similarly Sin3A+Sin5A= 2sin4AcosA
2sin4Acos3A + 2sin4AcosA = 2sin4A(cos3A+cosA) = 2Sin4A (2cos2AcosA) = 4sin4Acos2AcosA
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