Question

Sin A/sin(90°-A)/1+sin(90°-A) - cos A/cos(90°-A)=sec A cosec A

Answer 1

$\frac{Sin A}{sin(90°-A)} + \frac{cos A}{cos(90°-A)} = sec A.cosec A \: \\ \frac{Sin A}{cosA}+ \frac{cos A}{sinA} = sec A.cosec A \: \\ \frac{sin ^{2} A +cos^{2} A }{cosA. sinA } \: = sec A.cosec A \: \\ \frac{1}{ {cosA. sinA } } = sec A..cosec A \\ sec A.cosec A = sec A.cosec A \\ LHS \: = RHS \:$

Answer 2

❇️hope this helps!!! ❇️

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