Question

sin A/sin (90°- A) + cos A/ cos (90°- A) = sec (90° - A) cosec (90°-A)​

Answer 1

Step-by-step explanation:

sin A/sin (90°- A) + cos A/ cos (90°- A) = sec (90° - A) cosec (90°-A)

tan A + cot A = Cosec A . Sec A

Tan A +cot A

sinA/cosA +cos A/sin A

on taking LCM

(Sin²A+cos²A)/sinA cos A

As we know sin²A+cos²A=1

1/sinA cosA⇒cosecA secA

{1/cosA=secA, 1/sinA=cosecA}

Answer 2

Refer to the attachment

by the way

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