Question

(sin a . sin b)^2 - (cos a sin b)^2​

Answer 1

Answer:

Taking (sin B)^2 common :

= (sin B)^2 (cos^2 A - sin^2 A)

= (sin B)^2 (cos 2A)

= (2 . sin B . sin B . cos 2A)/2

= ((1 - cos 2B). cos 2A)/2

PLS MARK BRAINLIEST AND FOLLOW ME FOR MORE ANSWERS.

Answer 2

{(Sin a . sin b)+ (cos a . sin b)} {(Sin a . sin b) - (cos a . sin b) }