((sin A + sin B)/(cosA-cosB))+((cosA+cosB)/(sinA-sin B))= 0
how to prove that
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Step-by-step explanation:
L.H.S=((sinA+sinB)/(cosA-cosB))+((cosA+cosB)/(sinA-sinB))
=sin^2A-sin^2B+cos^2A-cos^2B/(cosA-cosB)(sinA-sinB)
=1-1/(cosA-cosB)(sinA-sinB)
=0
=R.H.S
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