sin A + sin B + sin(A + B)÷
sin A + sin B - sin(A + B)
Answers
Answered by
6
Step-by-step explanation:
Answer
sinAsinB
sin(A−B)
+
sinBsinC
sin(B−C)
+
sinCsinA
sin(C−A)
=0
=
sinAsinB
sinAcosB−cosAsinB
+
sinBsinC
sinBcosC−cosBsinC
+
sinCsinA
sinCcosA−cosCsinA
=cotB−cotA+cotC−cotB+cotA−cotC
=0 (proved)
Answered by
0
Answer:
sin A + sin B + sin(A + B)÷
sin A + sin B - sin(A + B)
Step-by-step explanation:
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SinA . Sin(B - C) + SinB . Sin(C - A) + SinC . Sin(A - B)=0
=>SinA . (SinBCosC - CosBSinC) + SinB . (SinCCosA - CosCSinA) + SinC . (SinACosB - CosASinB)
=>SinASinBCosC -SinACosBSinC + SinBSinCCosA - SinBCosCSinA + SinCSinACosB - SinCCosASinB
All get cancelled
=>0
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