sin A + sin B + sin(A + B)÷
sin A + sin B - sin(A + B)
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Answered by
4
Answer:
Ans: 0
Step-by-step explanation:
sin(A−B)
+
sinBsinC
sin(B−C)
+
sinCsinA
sin(C−A)
=0
=
sinAsinB
sinAcosB−cosAsinB
+
sinBsinC
sinBcosC−cosBsinC
+
sinCsinA
sinCcosA−cosCsinA
=cotB−cotA+cotC−cotB+cotA−cotC
=0 (proved)
Answered by
22
Answer:
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Step-by-step explanation:
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