sin A + sin B + sin(A + B)÷
sin A + sin B - sin(A + B)
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Answer:
Sin(A+B)=sinA.cosB+cosA.sinB
So , according to above equation
sin(A+B)=sinA+sinB is false.
Justification:
Let A=60
∘
B=30
∘
LHS=sin(A+B)=sin(60
∘
+30
∘
)=sin90
∘
=1
RHS=sinA+sinB=sin60
∘
+sin30
∘
=
2
3
+
2
1
Hence, LHS
=RHS.
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