Question

sin A (sina+B) is equal to​

Answer 1

Answer:

As it is given= sinA.sin(A+B)

by using Sin(A+B)=sinAcosB+cosAsinB

⇒sinA(sinAcosB+cosAsinB)

∴sinA.sin(A+B)=sin²AcosB+sinAcosAsinB

Answer 2

Explanation:

as it is given= sinA.sin(A+B)

by using Sin(A+B)=sinAcosB+cosAsinB

⇒sinA(sinAcosB+cosAsinB)

∴sinA.sin(A+B)=sin²AcosB+sinAcosAsinB