Physics, asked by mananjain5165, 7 months ago

sin A (sina+B) is equal to

Answers

Answered by ItsCrazyDaRk02

6

Answer:

As it is given= sinA.sin(A+B)

by using Sin(A+B)=sinAcosB+cosAsinB

⇒sinA(sinAcosB+cosAsinB)

∴sinA.sin(A+B)=sin²AcosB+sinAcosAsinB

Answered by Anonymous

4

Explanation:

as it is given= sinA.sin(A+B)

by using Sin(A+B)=sinAcosB+cosAsinB

⇒sinA(sinAcosB+cosAsinB)

∴sinA.sin(A+B)=sin²AcosB+sinAcosAsinB

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