sin A + sinB÷cos A + cosB= tan(A+B/2)
Answers
Answered by
1
Answer:
see below
Explanation:
sin A + sinB÷cos A + cosB
= 2[sin(A+B)/2]cos[(A-B)/2] ÷ 2cos[(A+B)/2]cos[(A-B)/2]
=sin(A+B)/2 ÷ cosA+B)/2
= tan(A+B)/2
Similar questions