Question

Sin(-A) tan(180°+A) tan(90+A) ÷ cot(90-A) cos(360-A) sin(180°-A)

Answer 1

Answer:

Answer:

We know that,

cot(180° + x) = cot x (quadrant III)

cot(90° + x) = -tan x (quadrant II)

cot(360° – x) = -cot x (quadrant IV)

tan A + cot(180° + A) + cot(90° + A) + cot(360° – A)

= tan A + cot A – tan A – cot A