sin A × tan A ÷ 1-cos A= 1+ sec A
Answers
Answered by
1
Step-by-step explanation:
sin A × tan A ÷ 1-cos A= 1+ sec A
Taken lhs
sin A × tan A ÷ 1-cos A
sinA * sin A/ cos A ÷ 1-cos A
sin^2 A/ cos A ÷ 1-cos A
(1- cos^2 A)/ cos A ÷ (1-cos A)
(1+ cos A) ( 1 - cosA) / cos A ÷ (1-cos A)
cut (1-cos A)
(1+ cos A)/ cos A
1/ cos A. + cosA/ cosA
sec A + 1. RHS
Similar questions