Sin A * tan A/1 - cos A = 1 + Sec A
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LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved
sharansss114:
Bro THE Is 1 plus sec A
bhai 1+secA= secA+1 hota h ,ye kya baat hui yrr
but u have proved 1/(sec a - tan A)
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this is the way to prove
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