Question

sin A tan A
-= 1 + sec A
1-cos A​

Answer 1

Answer:

(Sin  a)  x  (tan  a)  =  1  +  (sec  a)  x  1  -  (cos  a)

sin^2x=1-cos^2x

now comes to ur question

sinxtanx/1-cosx

open tanx

sinxsinx/cosx(1-cosx)

sin^2x/cosx(1-cosx)

now open sin^2x

1-cos^2x/cosx(1-cosx)

we know a^2-b^2=(a+b)(a-b)

use it

(1+cosx)(1-cosx)/cosx(1-cosx)

weget

(1+cosx)/cosx

1/cosx+cosx/cosx

secx+1

Answer 2

Answer: proved below plz mark BRAINIEST