Question

sin Acasa
11 From the adjacent figure
prove that sina + cos'assin'e + cose
ii) prove that sec'a-tan'a see-tan'e
13ems
De
0
Sems​

Answer 1

Answer:

sinA=√1−cos2A=√1−25169=√169−25169= = √144169=1213 ,. and. tanA=sinAcosA=1213513= 1213⋅135=125 . Answer link ... the side adjacent to A=5andthe hypotenuse =13 ... opp=√132−52= 12.

Step-by-step explanation:

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Answer 2

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