Question

Sin(alpha) = √3/2 and cos(beta) = 0, then what will be the value of beta - alpha?

Answer 1

Answer:

$\beta - \alpha = 30°$

Step-by-step explanation:

To find the value of

$\beta - \alpha$

Solve the given trigonometric equations

$\sin( \alpha ) = \frac{ \sqrt{3} }{2} \\ \\ we \: know \: that \\ \\ \sin(60°) = \frac{ \sqrt{3} }{2} \\ \\ \sin( \alpha ) = \sin(60°) \\ \\ \alpha = 60°...eq1$

By the same way

$\cos( \beta ) = 0 \\ \\ we \: know \: that \\ \\ \cos(90°) = 0 \\ \\ \cos( \beta ) = \cos(90°) \\ \\ \beta = 90°...eq2$

To find

$= \beta - \alpha \\ \\ = 90° - 60° \\ \\ \beta - \alpha = 30°$

Hope it helps you.

Answer 2

The value of$\beta - \alpha$is 30°.

Step-by-step explanation:

We have,

$\sin \alpha=\dfrac{\sqrt{3} }{2}$ and

$\cos \beta=0$

To find, the value of$\beta - \alpha=?$

$\sin \alpha=\dfrac{\sqrt{3} }{2}=\sin 60$

⇒$\alpha=$60°

Also,

$\cos \beta=0=\cos 90$

⇒$\beta=$90°

∴ $\beta-\alpha$=90° - 60° = 30°

Hence, the value of$\beta - \alpha$ is 30°.