Question

sin(alpha+beta)÷sin(alpha-beta)=a+b÷a-b thentanalpha÷tanbeta​

Answer 1

Answer:

sin(alpha+beta)/sin(,alpha-beta)=a+b/a-b

sin(alpha)cos(beta)+cos(alpha)sin(beta)/sin(alpha)cos(beta)-cos(alpha)sin(beta)=a+b/a-b

sin(alpha)cos(beta)+cos(alpha)sin(beta)+sin(alpha)cos(beta)-cos(alpha)sin(beta)/sin(alpha)cos(beta)+cos(alpha)sin(beta)-(sin(alpha)cos(beta)-cos(alpha)sin(beta)=(a+b)+(a-b)/(a+b)-(a-b)

2sin(alpha)cos(beta)/2cos(alpha)sin(beta)=2a/2b

sin(alpha)cos(beta)/cos(alpha)sin(beta)=a/b

tan(alpha)/tan(beta)=a/b