Math, asked by shadowgirl, 11 months ago

(sin alpha +cos alpha )(tan alpha -cot alpha)=sec alpha +cosec alpha​

Answers

Answered by skjalal
3

Answer:

(sinA+cosA)(tanA -cotA)

=(sinA+cosA)(sin^2A-cos^2A/sinAcosA)

=-(sinA+cosA)(cos^2A-sin^2A/1/2×2sinAcosA)

that is your turn to complete

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