Math, asked by san5294, 10 months ago

(sin alpha+cosec alpha)^2+(cos alpha+sec alpha)^2=tan^2 alpha+cot^2 alpha+7(prove this)​

Answers

Answered by Siddharta7
1

Step-by-step explanation:

Given,

(sinα + cosecα)² + (cosα + secα)²

⇒ sin²α + cosec²α + 2sinαcosecα + cos²α + sec²α + 2cosαsecα

⇒ 1 + (1 + cot²α) + 2 * sinα * 1/sinα + 1 + tan²α + 2 * cosα * 1/cosα

⇒ 1 + 1 + cot²α + 2 + 1 + tan²α + 2

⇒ tan²α + cot²α + 7

Hope it helps!

Answered by Anonymous
6

Answer:

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