sin alpha is equal to a sin beta and Cos Alpha is equal to b cos beta then tan beta is equal to
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sinα = a sinβ ........1
cosα = b cosβ .........2
sinα/cosα = a sinβ/b cosβ
(Transposing a/b to the other side as b/a)
sinβ/cosβ = b sinα/a cosα
tanβ = b sinα/a cosα
cosα = b cosβ .........2
sinα/cosα = a sinβ/b cosβ
(Transposing a/b to the other side as b/a)
sinβ/cosβ = b sinα/a cosα
tanβ = b sinα/a cosα
☺ Hope this Helps ☺
Prashanth92:
answer is root over 1-b^2/a^2-1
Answered by
1
sin alpha = a sin beta ......1
cos alpha = b cos beta .......2
Now,
sin alpha÷cos alpha =a sin beta ÷b cos beta
tan alpha = a÷b tan beta
tan beta =b sin alpha ÷ a cos alpha
Hope this will help you
cos alpha = b cos beta .......2
Now,
sin alpha÷cos alpha =a sin beta ÷b cos beta
tan alpha = a÷b tan beta
tan beta =b sin alpha ÷ a cos alpha
Hope this will help you
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