Question

Sin alpha is equal to root 3 by 2 and Cos beta is equal to zero find the value of beta _ alpha

Answer 1

Answer:

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Answer 2

Answer:

$\beta - \alpha =45^{\circ}$

Step-by-step explanation:

Given :$Sin \alpha = \frac{\sqrt{3}}{2}$

           $Cos \beta = 0$

To Find : find the value of beta - alpha

Solution :

$Sin \alpha = \frac{\sqrt{3}}{2}$

$\alpha =Sin^{-1}(\frac{\sqrt{3}}{2})$

$\alpha =45^{\circ}$

$Cos \beta = 0$

$\beta =Cos^{-1} 0$

$\beta =90^{\circ}$

$\beta - \alpha = 90^{\circ}-45^{\circ} = 45^{\circ}$

Hence$\beta - \alpha =45^{\circ}$