sinα=asinβ and cosα=bcosβ then tanα=
JinKazama1:
Just divide
a/b tan(β)
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Hey dear here is ur answer ******
____________________
sin @=a sin beta, cos@=bcos beta
so,tan @=sin @/cos @
=a sin beta/bcos beta
=a/b tan beta
Hope it will help u@@@@@####
____________________
sin @=a sin beta, cos@=bcos beta
so,tan @=sin @/cos @
=a sin beta/bcos beta
=a/b tan beta
Hope it will help u@@@@@####
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