Question

Sin (ax+b) Cos (ax+b)​

Answer 1

Answer:

ANSWER

∫sin(ax+b)cos(ax+b)dx

u=sin(ax+b)⇒dx=

acos(ax+b)

1

​

du

∫sin(ax+b)cos(ax+b)=

a

1

​

∫udu

=

2a

u

2

​

=

2a

sin

2

(ax+b)

​

∫sin(ax+b)cos(ax+b)dx=

2a

sin

2

(ax+b)

​

+C

Step-by-step explanation: