Math, asked by son83, 1 year ago

sin(B+ A)+ cos(B - A)÷
sin(B - A) + cos(B + A)​

Answers

Answered by Anonymous
1

Step-by-step explanation:

=sin(B+A)+cos(B-A)/sin(B-A)+cos(B+A)

=(sinB*cosA + cosB*sinA + cosB*cosA + sinB*sinA)/(sinB*cosA - cosB*sinA + cosB*cosA - sinB*sinA)

= sinB(cosA+sinA)+cosB(sinA+cosA)/sinB(cosA-sinA)+cosB(cosA-sinA)

= (sinB+cosB)*(sinA+cosA)/(sinB+cosB)*(cosA-sinA)

= cosA+sinA/cosA-sinA

= (cosA+sinA/cosA-sinA)*(cosA+sinA/cosA+sinA)

= cos²A+sin²A+2sinA*cosA/cos²A-sin²A

= 1+ sin2A / cos2A

= sec2A + tan2A

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