Question

sin(B-C)/sin A=b2-c2/a2​

Answer 1

by multiplying 2 in both numerator and denominator we get ..

2sin ( B-C ) / 2 sin A

{ sin in numr. and sin in denom. will be canceled }

2 (B - C ) / 2 sin A

2 B - 2 c / 2 A

hence proved

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