Question

Sin(B-C) /SinBsinC+sin(C-A) /sinCsinA+sin(A-B) /sinAsinB​

Answer 1

Answer:

sin(A−B)

​  

+  

sinBsinC

sin(B−C)

​  

+  

sinCsinA

sin(C−A)

​  

=0

=  

sinAsinB

sinAcosB−cosAsinB

​  

+  

sinBsinC

sinBcosC−cosBsinC

​  

+  

sinCsinA

sinCcosA−cosCsinA

​  

 

=cotB−cotA+cotC−cotB+cotA−cotC

=0  (proved)

Step-by-step explanation:

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