Math, asked by aayza5293, 1 year ago

Sin B/sin C= c-acocB/b-acosC

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Answered by rohityadav1829

0

Given: ΔABC. Prove that sinb/sinc = c- acosb/b-acosc. Use cosine formulas: cosb = (a²+c² - b²)/2ac and cosc ...

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