Physics, asked by charan888, 1 year ago

sin c =1/n12 can we find critical angle of water using above equation

Answers

Answered by Atulkrishnan
10
use the snell's law:
                               n.sin(i)=m.sin(r)
                       in the equation,put
                                  n=refractive index of water(=4/3)
                                  r=90 degree
                                  m=refractive index of air(=1)
                                 then ' i ' will automatically become critical angle c.
As u know,critical angle is an angle above which refraction of right rays travelling from denser to rarer does not take place....

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