Question

sinΦ=c/√c2+d2,d>0.find cosΦ&tanΦ

Answer 1

Answer:

cos Φ = c+d4/c , tan Φ = 1

Step-by-step explanation:

see,

sinΦ = c/c2+d2  ; sin Φ = Perpendicular/Hypotenuse

So when we both Perpendicular and Hypotenuse,

we should get the Base. For that we use p^2+h^2 = b^2

So , as per that; p^2+h^2 = b^2                    

                         : (c2)^2 + (d2)^2 = b^2                  { we got the values from sinΦ}

                         : (c^2 x 4 ) + (d^2 x 4) = b^2      { on squaring (c2)^2 + (d2)^2 )

                         : c^2d^2*8                                 { on addding (c2)^2 + (d2)^2 }

                         :$\sqrt{c^{2} d^{2} 8 }$                             { underroot :(c2)^2 + (d2)^2}

                         : b = c+d4

so, We got the Base = c+d 4

now; cosФ = Base/Perpendicular =  c+d4/c

now; tan Ф = sinФ/cosФ

⇒ (c/c2+d2)/(c+d4/c)

then cut , c with c 2 and 2 with 4

then the answer becomes c+d/c+d ⇒ 1

Hope you understand;