Question

Sin C+ Sin D =.......​

Answer 1

Answer:

sin C + sin D = 2 sin[(C + D) / 2]cos[(C - D) / 2]

good luck :)))

Step-by-step explanation:

Answer 2

Sin C + Sin D →

$2 \sin( \frac{c + d}{2} ) . \cos( \frac{c - d}{2} )$

This is the formula to transform the sum or difference into Product .

Some other formulae related to this are

SinC - sinD =

$2 \sin( \frac{c - d}{2} ) . \cos( \frac{c + d}{2} )$

CosC + CosD =

$2 \cos( \frac{c + d}{2} ). \cos( \frac{c - d}{2} )$

CosD-CosC =

$2 \sin( \frac{c + d}{2} ) . \sin( \frac{d - c}{2} )$

Hope it helps