sin c-sin D=2coos (c+d/2)×sin (c-d/2) prove that
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Solution:
Let, C be x + y and D be x - y
Now,
» x + y = C
» x - y = D
On solving we get,
» x = (C + D)/2 and y = (C - D)/2
Now,
=> sin C - sin D
Substitute C = x + y and D = x - y, we get
=> sin (x + y) - sin (x - y)
= sin x cos y + cos x sin y - [sin x cos y - cos x sin y]
= 2 cos x sin y
Substituting values of x and y, we get
= 2 cos (C + D)/2 sin (C - D)/2
Hence, proved.
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