Sinα-cosα=0 then find the value of sin^4+cosα^4
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Answered by
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Hey !!
Check the attachment.
Hope it helps :)
Check the attachment.
Hope it helps :)
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sibaprasadp7693:
Thx brother
Answered by
5
heya friends !!!
sin@-cos@=0.
then. ...sin@=cos@
.and since , @=45°>>>
now,,,,. from given question.
sin^4@+cos^4
=>sin^4(45°)+cos^4(45°)
"=>sin^4(45°)+cos^4(45°)
=>since ,sin45°=1 /√2 and cos45=1/√2...
now,,,we have ....
=>[1/√2]^4+[1/√2]^4
=>1/4+1/4
=>2/4
=>1/2...Ans.........
hope it help you..
@Rajukumar☺☺☺☺
sin@-cos@=0.
then. ...sin@=cos@
.and since , @=45°>>>
now,,,,. from given question.
sin^4@+cos^4
=>sin^4(45°)+cos^4(45°)
"=>sin^4(45°)+cos^4(45°)
=>since ,sin45°=1 /√2 and cos45=1/√2...
now,,,we have ....
=>[1/√2]^4+[1/√2]^4
=>1/4+1/4
=>2/4
=>1/2...Ans.........
hope it help you..
@Rajukumar☺☺☺☺
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