sin/cos = 1/ tan or tan
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sin/cos = tan............
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Answer:
Step-by-step explanation:
LHS
= cosA/1-(sinA/cosA) + sinA/1-(cosA/sinA)
=cosA/(cosA-sinA)/cosA+sinA/(sinA-cosA)/sinA
=cosA ×cosA/cosA-sinA+(sinA×sinA)/sinA-cosA
=cos^2 A/cosA-sinA + sin^2 A/sinA-cosA
=cos^2 A-sin^2 A/cosA-sinA
=(cosA+sinA) (cosA-sinA)/cosA-sinA
=cosA+sinA
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