Question

.(sinθ+cosθ)²+(sinθ-cosθ)²=


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Answer 1

Step-by-step explanation:

sin²A+cos²A+sin²A+cos²A+2sinAcosA-2sinAcosA

=2

Answer 2

Answer:2,sin^2+cos^2=1

Step-by-step explanation:(sina+cosa)^2(sina+cosa)^2

(a+b)^2=a^2+b^2+2ab, (a-b)^2=a^2+b^2-2ab,sin^2+cos^2=1

=Sin^2+cos^2+2sina×cosa+sin^2+cos^2-2sina×cosa

(Since +2sina×cosaand -2sina×cosa are cancelled)

=Sin^2a+cos^2a+sin^2a+cos^2a

1+1=2 (since given sin^2+cos^2=1)