Question

(sin+cos)^2+(sin-cos)^2=2​

Answer 1

Answer:

hi friends

Step-by-step explanation:

LHS

= (sin +cos)^2 + (sin - cos)^2

[expand by identity (a+b)^2 & (a-b)^2]

ie, sin^2 +2sin.cos +cos^2 + sin2 -2sin.cos + cos^2

=>1+1

[sin2 + cos2 =1,, and 2sin.cos & -2sin.cos cancelled]

=> 2

hence proved

hope this answer is helpful

thank u