sin θ cos(900-θ) + cos θ sin (900-θ) =
adityaaryaas:
Is it 90 degree or 900 degree ?
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Answer:
Sin θ cos(90°-θ) + cos θ sin (90°-θ) = 1
Sin θ cos(900°-θ) + cos θ sin (900°-θ) = 0
Step-by-step explanation:
Sin θ cos(90°-θ) + cos θ sin (90°-θ)
Using formula Sin(A + B) = SinACosB + CosASinB
= Sin(θ + 90°-θ)
= Sin90°
= 1
Sin θ cos(90°-θ) + cos θ sin (90°-θ) = 1
or
Sin θ cos(90°-θ) + cos θ sin (90°-θ)
using cos(90°-θ) = Sinθ & sin (90°-θ) = Cosθ
= SinθSinθ + cos θ cos θ
= Sin²θ + cos²θ
= 1
or if we consider it 900°
Sin θ cos(900°-θ) + cos θ sin (900°-θ)
900° = 2*360° + 180°
= Sin θ cos(180°-θ) + cos θ sin (180°-θ)
= Sin(θ + 180°-θ)
= Sin 180°
= 0
Sin θ cos(900°-θ) + cos θ sin (900°-θ) = 0
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